bash - Loop for change the column - how not mistake $ of column with $i -

i make loop change columns in awk condition. however, $ symbol making mistake replacement "i". idea how fix it?

#!/bin/bash in {2..5} awk '$$i>=10 && $$i<=20' permut1.txt >> out.txt done 

input:

abc 1 1 2 3 4 bbb 0 1 2 0 1 ccc 1 1 0 2 2 ddd 0 1 3 1 3 fff 15 15 4 15 15 ggg 15 15 15 15 15 

i want output:

ggg 15 15 15 15 15 

in awk, $ prefix operator argument must non-negative integer. that's quite different meaning of $ in bash.

the easiest way pass variable bash awk use -v var=value command line option in awk command:

awk -v field=2 '$field >= 10 && $field <= 20' permut1.txt 

the above print lines second field between 10 , 20. iterate in bash multiple scans of data, each 1 scanning different column:

for in 2 3 4;   awk -v field=$i '$field >= 10 && $field <= 20' permut1.txt done 

but suspect trying iterate in awk on fields, , print lines satisfy 3 tests. again, fact awk $ operator can make relatively simple. awk feature simplifies logic next command, reads next input line , restarts pattern matching loop. makes easy require 3 tests match:

awk '{ (field = 2; field < 5; ++field) {          if ($field < 10 || $field > 20) next;        }        # can here if none of fields outside        # range. $0 entire line.        print $0;      }' permut1.txt 

because default pattern action precisely print $0, can shorten script:

awk '{ (field = 2; field < 5; ++field)           if ($field < 10 || $field > 20) next;        }      } 1' permut1.txt 

the 1 @ end condition true, no action (or, in other words, default action); if preceding rule doesn't execute next command of fields, 1 condition executed, , default action cause line printed.