using cat command with variable unix -

sh temp1.sh gold.txt silver.txt 2 gold.txt $2 

silver second gold. unique position in competition.

cat: cannot open $2 

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tstetlx () /appl/edw/apps/scripts/scenario1> vi temp1.sh i=$# echo $i echo $1 echo $`echo $i` #cat "$`echo $i`" cat $2 cat "\$$i" 

the below command not printing contents of second file passed argument file.

cat "\$$i" 

not clear me trying do. consider using $1 or $2.

the reason line fails because parameter cat literally $2 - no attempt shell substitute $2 if variable.

this 1 way handle problem. note bash solution.

i=$# echo $i echo $1 echo $`echo $i` #cat "$`echo $i`" cat $2 cat "\$$i" declare -a arr=( "$0" $@ ) echo  ${arr[i]} cat ${arr[i]}