Making dictionary construction shorter in Python using defaultdict? -


is there anyway can make code-block shorter? seems written more efficiently:

combs = defaultdict(list) zf in zipfiles:     chunks = zf.split('_')     combs[chunks[0] + '_' + chunks[1]].append(zf)

maybe searching this:

combs = defaultdict(list) zf in zipfiles:     combs["_".join(zip.split("_")[0:2]].append(zf)

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