Regex to Match All Whitespace After Word -

i have strings this: "2015/08/this filename has whitespace .jpg"

i need match whitespace characters in strings. have "2015/08/ , end ".

i'm using sublime text 2 search , replace in sql db dump. i'm @ loss on how match. know can match whitespace \s, have no clue how contain groups.

as per comment, expression should work for string has same number of opening/closing double quotes:

\s+(?=(?:(?:[^"]*"){2})*[^"]*"[^"]*$)

see demo here. look-ahead checking odd number of double quotes until end of file.

another approach define boundary \g , trim beginning of match \k:

(?:"\d{4}\/\d{2}\/|(?!^)\g)[^"\s]*\k\s(?=[^"]*")

the regex finds match:

(?:"\d{4}\/\d{2}\/|(?!^)\g) - when substring starts numbers 2015/12/ or after successful match
[^"\s]*\k - matches characters not whitespace or " , omits them due \k operator
\s - here matches whitespace symbol
(?=[^"]*") - look-ahead checking presumably inside double quotes.

replacing spaces with, say, %20 results in:

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