mongodb - Updating fields efficiently without losing data -

i'm getting feet wet pymongo, , seems easy task i'm not sure best way it.

i have dictionary of member objects, each of has dictionary (key-value pairs of data). go through dictionary of member objects, , update database:

1. writing every field present in member object db, and
2. leaving unchanged other fields present in db member id not present in member object.

here's best shot, running extremely slow, i'm guessing there's better way. (maybe one-liner?)

in code, self.members dictionary of members i'm iterating through, , member.structure() returns dictionary of member object's data.

for m in sorted(self.members.values(), key=lambda val:val.session) : ## each member     if mcollection.find_one({'id':m.id}) none: ## if there no db entry matching member id         print("\tmember {0} wasn't present in db. inserting.".format(m.id))         mcollection.insert(m.structure())         ## insert full dictionary     else: ## if there matching db entry         (k,v) in m.structure().items():  ## each entry in member's dictionary             mcollection.update( {'id':m.id}, {'$set': {k:v}}, upsert=true  ) ## set member's field value given in dictionary 

for (k,v) in m.structure().items():  ## each entry in member's dictionary     mcollection.update( {'id': 'm.id'}, {'$set': {k:v}}, upsert=true  ) ## set member's field value given in dictionary 

yes, insane. every k/v pair make separate request! should setting them @ once.

mcollection.update( {'id': 'm.id'}, {'$set': m.structure()})