java - Best way to convert Locale properties names to normal names -

i reading list of file property file names bundle. need replace file contents in following format {en_gb==my name}

i using replaceall method replace following characters "{en_gb" , "}" can have number of = symbols , string "en_" may end gb or au or us etc.

what best way replace these?

string s = "{en_gb==kt!hibio}";     system.out.println(s.replaceall("[{\\w}]", "")); 

you can use

string s = "{en_gb==pm!name}"; system.out.println(s.replaceall("\\{\\w+=+([^}]+)}", "$1")); 

see ideone demo

the regex matches

• \\{ - literal {
• \\w+ - 1 or more alphanumerics or underscore
• =+ - 1 or more equal signs
• ([^}]+) - matches , captures group 1 one or more characters other }
• } - closing brace

when substring matched, matched text replaced text captured group 1 $1.

your solution not work because regex have matching 1 character either { or non-word character (\w) , literal } because enclosed expression sqaure brackets, forming character class.

now, since regex quite generic, may further narrow down matching capabilities this:

system.out.println(s.replaceall("(?i)\\{en_[a-z]+=+([^}]+)}", "$1")); 

see another demo

this en_[a-z]+ required, , - (?i) makes pattern case insensitive - match en_us or en_us.

in case know there 2 letters after en_, use limiting quantifier {2}:

system.out.println(s.replaceall("(?i)\\{en_[a-z]{2}=+([^}]+)}", "$1"));